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Question

The area of the region S = {(x, y) : y2 $\le$ 8x, y $\ge$ $\sqrt2$x, x $\ge$ 1} is

${{13\sqrt 2 } \over 6}$
${{11\sqrt 2 } \over 6}$
${{5\sqrt 2 } \over 6}$
${{19\sqrt 2 } \over 6}$

Solution

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