Decarboxylation of all six possible forms of diaminobenzoic acids C6H3(NH2)2COOH yields three products A, B and C. Three acids give a product 'A', two acids gives a product 'B' and one acid give a product 'C'. The melting point of product 'C' is

Question

Decarboxylation of all six possible forms of diaminobenzoic acids C₆H₃(NH₂)₂COOH yields three products A, B and C. Three acids give a product 'A', two acids gives a product 'B' and one acid give a product 'C'. The melting point of product 'C' is

63$^\circ$C

90$^\circ$C

104$^\circ$C

142$^\circ$C

Solution

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