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Question

If ${\cos ^{ - 1}}\left( {{y \over 2}} \right) = {\log _e}{\left( {{x \over 5}} \right)^5},\,|y| < 2$, then :

${x^2}y'' + xy' - 25y = 0$
${x^2}y'' - xy' - 25y = 0$
${x^2}y'' - xy' + 25y = 0$
${x^2}y'' + xy' + 25y = 0$

Solution

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