If ${{dy} \over {dx}} + {{{2^{x - y}}({2^y} - 1)} \over {{2^x} - 1}} = 0$, x, y > 0, y(1) = 1, then y(2) is equal to :

Question

$2 + {\log _2}3$

$2 + {\log _3}2$

$2 - {\log _3}2$

$2 - {\log _2}3$

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