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Question

${\sin ^1}\left( {\sin {{2\pi } \over 3}} \right) + {\cos ^{ - 1}}\left( {\cos {{7\pi } \over 6}} \right) + {\tan ^{ - 1}}\left( {\tan {{3\pi } \over 4}} \right)$ is equal to :

${{11\pi } \over {12}}$
${{17\pi } \over {12}}$
${{31\pi } \over {12}}$
$-$${{3\pi } \over {4}}$

Solution

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