A projectile is launched at an angle '$\alpha$' with the horizontal with a velocity 20 ms$-$1. After 10 s, its inclination with horizontal is '$\beta$'. The value of tan$\beta$ will be : (g = 10 ms$-$2).

Question

A projectile is launched at an angle '$\alpha$' with the horizontal with a velocity 20 ms^$-$1. After 10 s, its inclination with horizontal is '$\beta$'. The value of tan$\beta$ will be : (g = 10 ms^$-$2).

tan$\alpha$ + 5sec$\alpha$

tan$\alpha$ $-$ 5sec$\alpha$

2tan$\alpha$ $-$ 5sec$\alpha$

2tan$\alpha$ $+$ 5sec$\alpha$

Solution

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