Your AI-Powered Personal Tutor
Question

Cu(s) + Sn2+ (0.001M) $\to$ Cu2+ (0.01M) + Sn(s)

The Gibbs free energy change for the above reaction at 298 K is x $\times$ 10$-$1 kJ mol$-$1. The value of x is __________. [nearest integer]

[Given : $E_{C{u^{2 + }}/Cu}^\Theta = 0.34\,V$ ; $E_{S{n^{2 + }}/Sn}^\Theta = - 0.14\,V$ ; F = 96500 C mol$-$1]

Correct Answer
983

Solution

Please login to view the detailed solution steps...

Go to DASH