If the system of equations $\alpha$x + y + z = 5, x + 2y + 3z = 4, x + 3y + 5z = $\beta$ has infinitely many solutions, then the ordered pair ($\alpha$, $\beta$) is equal to :

Question

If the system of equations

$\alpha$x + y + z = 5, x + 2y + 3z = 4, x + 3y + 5z = $\beta$

has infinitely many solutions, then the ordered pair ($\alpha$, $\beta$) is equal to :

(1, $-$3)

($-$1, 3)

(1, 3)

($-$1, $-$3)

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