Time period of a simple pendulum in a stationary lift is 'T'. If the lift accelerates with ${g \over 6}$ vertically upwards then the time period will be : (Where g = acceleration due to gravity)

Question

Time period of a simple pendulum in a stationary lift is 'T'. If the lift accelerates with ${g \over 6}$ vertically upwards then the time period will be :

(Where g = acceleration due to gravity)

$\sqrt {{6 \over 5}} T$

$\sqrt {{5 \over 6}} T$

$\sqrt {{6 \over 7}} T$

$\sqrt {{7 \over 6}} T$

Solution

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