An electron with speed v and a photon with speed c have the same de-Broglie wavelength. If the kinetic energy and momentum of electron are Ee and pe and that of photon are Eph and pph respectively. Which of the following is correct?

Question

An electron with speed v and a photon with speed c have the same de-Broglie wavelength. If the kinetic energy and momentum of electron are E_e and p_e and that of photon are E_ph and p_ph respectively. Which of the following is correct?

${{{E_e}} \over {{E_{ph}}}} = {{2c} \over v}$

${{{E_e}} \over {{E_{ph}}}} = {v \over {2c}}$

${{{p_e}} \over {{p_{ph}}}} = {{2c} \over v}$

${{{p_e}} \over {{p_{ph}}}} = {v \over {2c}}$

Solution

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