A proton, a neutron, an electron and an $\alpha$ particle have same energy. If $\lambda$p, $\lambda$n, $\lambda$e and $\lambda$a are the de Broglie's wavelengths of proton, neutron, electron and $\alpha$ particle respectively, then choose the correct relation from the following :

Question

A proton, a neutron, an electron and an $\alpha$ particle have same energy. If $\lambda$_p, $\lambda$_n, $\lambda$_e and $\lambda$_a are the de Broglie's wavelengths of proton, neutron, electron and $\alpha$ particle respectively, then choose the correct relation from the following :

$\lambda$_p = $\lambda$_n > $\lambda$_e > $\lambda$_a

$\lambda$_a < $\lambda$_n < $\lambda$_p < $\lambda$_e

$\lambda$_e < $\lambda$_p = $\lambda$_n > $\lambda$_a

$\lambda$_e = $\lambda$_p = $\lambda$_n = $\lambda$_a

Solution

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