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Question

Let E1 and E2 be two events such that the conditional probabilities $P({E_1}|{E_2}) = {1 \over 2}$, $P({E_2}|{E_1}) = {3 \over 4}$ and $P({E_1} \cap {E_2}) = {1 \over 8}$. Then :

$P({E_1} \cap {E_2}) = P({E_1})\,.\,P({E_2})$
$P(E{'_1} \cap E{'_2}) = P(E{'_1})\,.\,P(E{_2})$
$P({E_1} \cap E{'_2}) = P({E_1})\,.\,P({E_2})$
$P(E{'_1} \cap {E_2}) = P({E_1})\,.\,P({E_2})$

Solution

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