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Question

At 25$^\circ$C and 1 atm pressure, the enthalpies of combustion are as given below :

Substance ${H_2}$ C (graphite) ${C_2}{H_6}(g)$
${{{\Delta _c}{H^\Theta }} \over {kJ\,mo{l^{ - 1}}}}$ $ - 286.0$ $ - 394.0$ $ - 1560.0$

The enthalpy of formation of ethane is

+54.0 kJ mol$-$1
$-$68.0 kJ mol$-$1
$-$86.0 kJ mol$-$1
+97.0 kJ mol$-$1

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