The sum of all the real roots of the equation $({e^{2x}} - 4)(6{e^{2x}} - 5{e^x} + 1) = 0$ is

Question

The sum of all the real roots of the equation

$({e^{2x}} - 4)(6{e^{2x}} - 5{e^x} + 1) = 0$ is

${\log _e}3$

$ - {\log _e}3$

${\log _e}6$

$ - {\log _e}6$

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