Your AI-Powered Personal Tutor
Question

Let the maximum area of the triangle that can be inscribed in the ellipse ${{{x^2}} \over {{a^2}}} + {{{y^2}} \over 4} = 1,\,a > 2$, having one of its vertices at one end of the major axis of the ellipse and one of its sides parallel to the y-axis, be $6\sqrt 3 $. Then the eccentricity of the ellipse is :

${{\sqrt 3 } \over 2}$
${1 \over 2}$
${1 \over {\sqrt 2 }}$
${{\sqrt 3 } \over 4}$

Solution

Please login to view the detailed solution steps...

Go to DASH