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Question

Let the area of the triangle with vertices A(1, $\alpha$), B($\alpha$, 0) and C(0, $\alpha$) be 4 sq. units. If the points ($\alpha$, $-$$\alpha$), ($-$$\alpha$, $\alpha$) and ($\alpha$2, $\beta$) are collinear, then $\beta$ is equal to :

64
$-$8
$-$64
512

Solution

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