Question
If the sum of the squares of the reciprocals of the roots $\alpha$ and $\beta$ of
the equation 3x2 + $\lambda$x $-$ 1 = 0 is 15, then 6($\alpha$3 + $\beta$3)2 is equal to :
If the sum of the squares of the reciprocals of the roots $\alpha$ and $\beta$ of
the equation 3x2 + $\lambda$x $-$ 1 = 0 is 15, then 6($\alpha$3 + $\beta$3)2 is equal to :