A projectile is projected with velocity of 25 m/s at an angle $\theta$ with the horizontal. After t seconds its inclination with horizontal becomes zero. If R represents horizontal range of the projectile, the value of $\theta$ will be : [use g = 10 m/s2]

Question

A projectile is projected with velocity of 25 m/s at an angle $\theta$ with the horizontal. After t seconds its inclination with horizontal becomes zero. If R represents horizontal range of the projectile, the value of $\theta$ will be :

[use g = 10 m/s²]

${1 \over 2}{\sin ^{ - 1}}\left( {{{5{t^2}} \over {4R}}} \right)$

${1 \over 2}{\sin ^{ - 1}}\left( {{{4R} \over {5{t^2}}}} \right)$

${\tan ^{ - 1}}\left( {{{4{t^2}} \over {5R}}} \right)$

${\cot ^{ - 1}}\left( {{R \over {20{t^2}}}} \right)$

Solution

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