A vertical electric field of magnitude 4.9 $\times$ 105 N/C just prevents a water droplet of a mass 0.1 g from falling. The value of charge on the droplet will be : (Given : g = 9.8 m/s2)

Question

A vertical electric field of magnitude 4.9 $\times$ 10⁵ N/C just prevents a water droplet of a mass 0.1 g from falling. The value of charge on the droplet will be :

(Given : g = 9.8 m/s²)

1.6 $\times$ 10^$-$9 C

2.0 $\times$ 10^$-$9 C

3.2 $\times$ 10^$-$9 C

0.5 $\times$ 10^$-$9 C

Solution

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