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Question

In the following sequence of reactions a compound A, (molecular formula C6H12O2) with a straight chain structure gives a C4 carboxylic acid. A is :

$C{H_3} - C{H_2} - COO - C{H_2} - C{H_2} - C{H_3}$
$C{H_3} - C{H_2} - C{H_2} - COO - C{H_2} - C{H_3}$
$C{H_3} - C{H_2} - C{H_2} - O - CH = CH - C{H_2} - OH$

Solution

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