A free electron of 2.6 eV energy collides with a H+ ion. This results in the formation of a hydrogen atom in the first excited state and a photon is released. Find the frequency of the emitted photon. (h = 6.6 $\times$ 10$-$34 Js)

Question

A free electron of 2.6 eV energy collides with a H⁺ ion. This results in the formation of a hydrogen atom in the first excited state and a photon is released. Find the frequency of the emitted photon. (h = 6.6 $\times$ 10^$-$34 Js)

1.45 $\times$ 10¹⁶ MHz

0.19 $\times$ 10¹⁵ MHz

1.45 $\times$ 10⁹ MHz

9.0 $\times$ 10²⁷ MHz

Solution

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