If ${{dy} \over {dx}} = {{{2^{x + y}} - {2^x}} \over {{2^y}}}$, y(0) = 1, then y(1) is equal to : - DASH

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Question

If ${{dy} \over {dx}} = {{{2^{x + y}} - {2^x}} \over {{2^y}}}$, y(0) = 1, then y(1) is equal to :

log₂(2 + e)

log₂(1 + e)

log₂(2e)

log₂(1 + e²)

Solution

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