Let y = y(x) be the solution of the differential equation ${{dy} \over {dx}} = 2(y + 2\sin x - 5)x - 2\cos x$ such that y(0) = 7. Then y($\pi$) is equal to :

Question

Let y = y(x) be the solution of the differential equation

${{dy} \over {dx}} = 2(y + 2\sin x - 5)x - 2\cos x$ such that y(0) = 7. Then y($\pi$) is equal to :

$2{e^{{\pi ^2}}} + 5$

${e^{{\pi ^2}}} + 5$

$3{e^{{\pi ^2}}} + 5$

$7{e^{{\pi ^2}}} + 5$

Solution

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