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Question
If $\alpha$, $\beta$ are the distinct roots of x2 + bx + c = 0, then

$\mathop {\lim }\limits_{x \to \beta } {{{e^{2({x^2} + bx + c)}} - 1 - 2({x^2} + bx + c)} \over {{{(x - \beta )}^2}}}$ is equal to :
b2 + 4c
2(b2 + 4c)
2(b2 $-$ 4c)
b2 $-$ 4c

Solution

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