In Millikan's oil drop experiment, what is viscous force acting on an uncharged drop of radius 2.0 $\times$ 10$-$5 m and density 1.2 $\times$ 103 kgm$-$3 ? Take viscosity of liquid = 1.8 $\times$ 10$-$5 Nsm$-$2. (Neglect buoyancy due to air).
3.8 $\times$ 10$-$11 N
3.9 $\times$ 10$-$10 N
1.8 $\times$ 10$-$10 N
5.8 $\times$ 10$-$10 N
Solution
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