Let $$A = \left( {\matrix{ 1 & 0 & 0 \cr 0 & 1 & 1 \cr 1 & 0 & 0 \cr } } \right)$. Then A2025 $-$$ A2020 is equal to :

Question

Let $$A = \left( {\matrix{ 1 & 0 & 0 \cr 0 & 1 & 1 \cr 1 & 0 & 0 \cr } } \right)$. Then A²⁰²⁵ $-$$ A²⁰²⁰ is equal to :

A⁶ $-$ A