Let y(x) be the solution of the differential equation 2x2 dy + (ey $-$ 2x)dx = 0, x > 0. If y(e) = 1, then y(1) is equal to :

Question

Let y(x) be the solution of the differential equation

2x² dy + (e^y $-$ 2x)dx = 0, x > 0. If y(e) = 1, then y(1) is equal to :

log_e 2

log_e (2e)

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