If $\sum\limits_{r = 1}^{50} {{{\tan }^{ - 1}}{1 \over {2{r^2}}} = p} $, then the value of tan p is :

Question

${{101} \over {102}}$

${{50} \over {51}}$

100

${{51} \over {50}}$

Please login to view the detailed solution steps...