A particle of mass m is suspended from a ceiling through a string of length L. The particle moves in a horizontal circle of radius r such that $r = {L \over {\sqrt 2 }}$. The speed of particle will be :
${\sqrt {rg} }$
${\sqrt {2rg} }$
${2\sqrt {rg} }$
${\sqrt {{{rg} \over 2}} }$
Solution
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