Two identical particles of mass 1 kg each go round a circle of radius R, under the action of their mutual gravitational attraction. The angular speed of each particle is :
$\sqrt {{G \over {2{R^3}}}} $
${1 \over 2}\sqrt {{G \over {{R^3}}}} $
${1 \over {2R}}\sqrt {{1 \over G}} $
${{2G} \over {{R^3}}}$
Solution
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