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Question
A particle executes simple harmonic motion represented by displacement function as

x(t) = A sin($\omega$t + $\phi$)

If the position and velocity of the particle at t = 0 s are 2 cm and 2$\omega$ cm s$-$1 respectively, then its amplitude is $x\sqrt 2 $ cm where the value of x is _________________.
Correct Answer
2

Solution

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