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Question

In the reported figure, a capacitor is formed by placing a compound dielectric between the plates of parallel plate capacitor. The expression for the capacity of the said capacitor will be :

(Given area of plate = A)

${{15} \over {34}}{{K{\varepsilon _0}A} \over d}$
${{15} \over 6}{{K{\varepsilon _0}A} \over d}$
${{25} \over 6}{{K{\varepsilon _0}A} \over d}$
${9 \over 6}{{K{\varepsilon _0}A} \over d}$

Solution

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