A particle starts executing simple harmonic motion (SHM) of amplitude 'a' and total energy E. At any instant, its kinetic energy is ${{3E} \over 4}$ then its displacement 'y' is given by :
y = a
$y = {a \over {\sqrt 2 }}$
$y = {{a\sqrt 3 } \over 2}$
$y = {a \over 2}$
Solution
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