Assertion A : If in five complete rotations of the circular scale, the distance travelled on main scale of the screw gauge is 5 mm and there are 50 total divisions on circular scale, then least count is 0.001 cm.Reason R :Least Count = ${{Pitch} \over {Total\,divisions\,on\,circular\,scale}}$In the light of the above statements, choose the most appropriate answer from the options given below :

Question

Assertion A : If in five complete rotations of the circular scale, the distance travelled on main scale of the screw gauge is 5 mm and there are 50 total divisions on circular scale, then least count is 0.001 cm.

Reason R :

Least Count = ${{Pitch} \over {Total\,divisions\,on\,circular\,scale}}$

In the light of the above statements, choose the most appropriate answer from the options given below :

A is not correct but R is correct.

Both A and R are correct and R is the correct explanation of A.

A is correct but R is not correct.

Both A and R are correct and R is NOT the correct explanation of A.

Solution

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