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Question
The value of $\cot {\pi \over {24}}$ is :
$\sqrt 2 + \sqrt 3 + 2 - \sqrt 6 $
$\sqrt 2 + \sqrt 3 + 2 + \sqrt 6 $
$\sqrt 2 - \sqrt 3 - 2 + \sqrt 6 $
$3\sqrt 2 - \sqrt 3 - \sqrt 6 $

Solution

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