A force $\overrightarrow F = (40\widehat i + 10\widehat j)N$ acts on a body of mass 5 kg. If the body starts from rest, its position vector $\overrightarrow r $ at time t = 10 s, will be :
$(100\widehat i + 400\widehat j)m$
$(100\widehat i + 100\widehat j)m$
$(400\widehat i + 100\widehat j)m$
$(400\widehat i + 400\widehat j)m$
Solution
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