A prism of refractive index $\mu$ and angle of prism A is placed in the position of minimum angle of deviation. If minimum angle of deviation is also A, then in terms of refractive index

Question

$2{\cos ^{ - 1}}\left( {{\mu \over 2}} \right)$

${\sin ^{ - 1}}\left( {{\mu \over 2}} \right)$

${\sin ^{ - 1}}\left( {\sqrt {{{\mu - 1} \over 2}} } \right)$

${\cos ^{ - 1}}\left( {{\mu \over 2}} \right)$

Solution

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