If qf is the free charge on the capacitor plates and qb is the bound charge on the dielectric slab of dielectric constant k placed between the capacitor plates, then bound charge qb an be expressed as :

Question

If q_f is the free charge on the capacitor plates and q_b is the bound charge on the dielectric slab of dielectric constant k placed between the capacitor plates, then bound charge q_b an be expressed as :

${q_b} = {q_f}\left( {1 - {1 \over {\sqrt k }}} \right)$

${q_b} = {q_f}\left( {1 - {1 \over k}} \right)$

${q_b} = {q_f}\left( {1 + {1 \over {\sqrt k }}} \right)$

${q_b} = {q_f}\left( {1 + {1 \over k}} \right)$

Solution

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