The instantaneous velocity of a particle moving in a straight line is given as $V = \alpha t + \beta {t^2}$, where $\alpha$ and $\beta$ are constants. The distance travelled by the particle between 1s and 2s is :
3$\alpha$ + 7$\beta$
${3 \over 2}\alpha + {7 \over 3}\beta $
${\alpha \over 2} + {\beta \over 3}$
${3 \over 2}\alpha + {7 \over 2}\beta $
Solution
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