From the given data, the amount of energy required to break the nucleus of aluminium $_{13}^{27}$Al is __________ x $\times$ 10^$-$3 J.

Mass of neutron = 1.00866 u

Mass of proton = 1.00726 u

Mass of Aluminium nucleus = 27.18846 u

(Assume 1 u corresponds to x J of energy)

(Round off to the nearest integer)