What should be the order of arrangement of de-Broglie wavelength of electron ($\lambda$e), an $\alpha$-particle ($\lambda$a) and proton ($\lambda$p) given that all have the same kinetic energy?
$\lambda$e = $\lambda$p = $\lambda$$\alpha$
$\lambda$e < $\lambda$p < $\lambda$$\alpha$
$\lambda$e > $\lambda$p > $\lambda$$\alpha$
$\lambda$e = $\lambda$p > $\lambda$$\alpha$
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