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Question
In the Young's double slit experiment, the distance between the slits varies in time as
d(t) = d0 + a0 sin$\omega$t; where d0, $\omega$ and a0 are constants. The difference between the largest fringe width and the smallest fringe width obtained over time is given as :
${{2\lambda D({d_0})} \over {(d_0^2 - a_0^2)}}$
${{2\lambda D{a_0}} \over {(d_0^2 - a_0^2)}}$
${{\lambda D} \over {d_0^2}}{a_0}$
${{\lambda D} \over {{d_0} + {a_0}}}$

Solution

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