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Question
The minimum and maximum distances of a planet revolving around the sun are x1 and x2. If the minimum speed of the planet on its trajectory is v0 then its maximum speed will be :
${{{v_0}x_1^2} \over {x_2^2}}$
${{{v_0}x_2^2} \over {x_1^2}}$
${{{v_0}x_1^{}} \over {x_2^{}}}$
${{{v_0}x_2^{}} \over {x_1^{}}}$

Solution

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