The values of $\lambda$ and $\mu$ such that the system of equations $x + y + z = 6$, $3x + 5y + 5z = 26$, $x + 2y + \lambda z = \mu $ has no solution, are :
$\lambda$ = 3, $\mu$ = 5
$\lambda$ = 3, $\mu$ $\ne$ 10
$\lambda$ $\ne$ 2, $\mu$ = 10
$\lambda$ = 2, $\mu$ $\ne$ 10
Solution
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