Let [x] denote the greatest integer less than or equal to x. Then, the values of x$\in$R satisfying the equation ${[{e^x}]^2} + [{e^x} + 1] - 3 = 0$ lie in the interval :
$\left[ {0,{1 \over e}} \right)$
[loge2, loge3)
[1, e)
[0, loge2)
Solution
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