Let $f:R - \left\{ {{\alpha \over 6}} \right\} \to R$ be defined by $f(x) = {{5x + 3} \over {6x - \alpha }}$. Then the value of $\alpha$ for which (fof)(x) = x, for all $x \in R - \left\{ {{\alpha \over 6}} \right\}$, is :
No such $\alpha$ exists
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Solution
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