The value of the integral $\int\limits_{ - 1}^1 {{{\log }_e}(\sqrt {1 - x} + \sqrt {1 + x} )dx} $ is equal to:

Question

${1 \over 2}{\log _e}2 + {\pi \over 4} - {3 \over 2}$

$2{\log _e}2 + {\pi \over 4} - 1$

${\log _e}2 + {\pi \over 2} - 1$

$2{\log _e}2 + {\pi \over 2} - {1 \over 2}$

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