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B > C > A

A > C > B

C > A > B

C > B > A

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During the nitration of aniline, the formation of meta-nitroaniline occurs due to the presence of the amino group ($-NH_2$), which is a meta-directing group in strongly acidic conditions. This is because the amino group can be protonated to form an ammonium ion ($-NH_3^+$), which directs incoming electrophiles to the meta position on the benzene ring. ### Step 1: Understanding the Reaction In the nitration of aniline, the electrophile is the nitronium ion ($NO_2^+$), which is generated from nitric acid ($HNO_3$) and sulfuric acid ($H_2SO_4$). The reaction can be summarized as follows: \[ \text{Aniline} + HNO_3 \rightarrow \text{Nitroaniline} \] ### Step 2: Directing Effects of Substituents The amino group ($-NH_2$) is an activating group that increases the electron density of the benzene ring, making it more reactive towards electrophilic substitution. However, under strongly acidic conditions, the amino group can become protonated, forming $-NH_3^+$. This protonation changes the directing effect of the group from ortho/para to meta. ### Step 3: Product Distribution The products formed during the nitration of aniline are: - Para-nitroaniline - Meta-nitroaniline - Ortho-nitroaniline The distribution of these products is approximately: - Para-nitroaniline: 51% - Meta-nitroaniline: 47% - Ortho-nitroaniline: 2% ### Step 4: Conclusion From the above distribution, we can conclude that the order of reactivity for the products formed during the nitration of aniline is: \[ C > B > A \] where: - C = Meta-nitroaniline - B = Para-nitroaniline - A = Ortho-nitroaniline Thus, the correct answer is **C > B > A**.

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