The area bounded by the curve 4y2 = x2(4 $-$ x)(x $-$ 2) is equal to :

Question

The area bounded by the curve 4y² = x²(4 $-$ x)(x $-$ 2) is equal to :

${\pi \over {16}}$

${\pi \over {8}}$

${3\pi \over {2}}$

${3\pi \over {8}}$

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