Consider a uniform wire of mass M and length L. It is bent into a semicircle. Its moment of inertia about a line perpendicular to the plane of the wire passing through the center is :
${1 \over 4}{{M{L^2}} \over {{\pi ^2}}}$
${1 \over 2}{{M{L^2}} \over {{\pi ^2}}}$
${2 \over 5}{{M{L^2}} \over {{\pi ^2}}}$
${{M{L^2}} \over {{\pi ^2}}}$
Solution
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